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Al Viro authored
->regset_get() takes task+regset+buffer, returns the amount of free space left in the buffer on success and -E... on error. buffer is represented as struct membuf - a pair of (kernel) pointer and amount of space left Primitives for writing to such: * membuf_write(buf, data, size) * membuf_zero(buf, size) * membuf_store(buf, value) These are implemented as inlines (in case of membuf_store - a macro). All writes are sequential; they become no-ops when there's no space left. Return value of all primitives is the amount of space left after the operation, so they can be used as return values of ->regset_get(). Example of use: // stores pt_regs of task + 64 bytes worth of zeroes + 32bit PID of task int foo_get(struct task_struct *task, const struct regset *regset, struct membuf to) { membuf_write(&to, task_pt_regs(task), sizeof(struct pt_regs)); membuf_zero(&to, 64); return membuf_store(&to, (u32)task_tgid_vnr(task)); } regset_get()/regset_get_alloc() taught to use that thing if present. By the end of the series all users of ->get() will be converted; then ->get() and ->get_size() can go. Note that unlike ->get() this thing always starts at offset 0 and, since it only writes to kernel buffer, can't fail on copyout. It can, of course, fail for other reasons, but those tend to be less numerous. The caller guarantees that the buffer size won't be bigger than regset->n * regset->size. That simplifies life for quite a few instances. Signed-off-by: Al Viro <viro@zeniv.linux.org.uk>
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