Commit 38c91407 authored by Hou Tao's avatar Hou Tao Committed by Jens Axboe

bfq: fix typos in comments about B-WF2Q+ algorithm

The start time of eligible entity should be less than or equal to
the current virtual time, and the entity in idle tree has a finish
time being greater than the current virtual time.
Signed-off-by: default avatarHou Tao <houtao1@huawei.com>
Reviewed-by: default avatarPaolo Valente <paolo.valente@linaro.org>
Signed-off-by: default avatarJens Axboe <axboe@kernel.dk>
parent 3b06b1a7
...@@ -52,7 +52,7 @@ struct bfq_entity; ...@@ -52,7 +52,7 @@ struct bfq_entity;
struct bfq_service_tree { struct bfq_service_tree {
/* tree for active entities (i.e., those backlogged) */ /* tree for active entities (i.e., those backlogged) */
struct rb_root active; struct rb_root active;
/* tree for idle entities (i.e., not backlogged, with V <= F_i)*/ /* tree for idle entities (i.e., not backlogged, with V < F_i)*/
struct rb_root idle; struct rb_root idle;
/* idle entity with minimum F_i */ /* idle entity with minimum F_i */
......
...@@ -1297,7 +1297,7 @@ static void bfq_update_vtime(struct bfq_service_tree *st, u64 new_value) ...@@ -1297,7 +1297,7 @@ static void bfq_update_vtime(struct bfq_service_tree *st, u64 new_value)
* *
* This function searches the first schedulable entity, starting from the * This function searches the first schedulable entity, starting from the
* root of the tree and going on the left every time on this side there is * root of the tree and going on the left every time on this side there is
* a subtree with at least one eligible (start >= vtime) entity. The path on * a subtree with at least one eligible (start <= vtime) entity. The path on
* the right is followed only if a) the left subtree contains no eligible * the right is followed only if a) the left subtree contains no eligible
* entities and b) no eligible entity has been found yet. * entities and b) no eligible entity has been found yet.
*/ */
......
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