signal: make sig_handler_ignored() return bool

sig_handler_ignored() already behaves like a boolean function.  Let's
actually declare it as such too.

Link: http://lkml.kernel.org/r/20180602103653.18181-8-christian@brauner.ioSigned-off-by: Christian Brauner <christian@brauner.io>
Reviewed-by: Andrew Morton <akpm@linux-foundation.org>
Cc: Al Viro <viro@zeniv.linux.org.uk>
Cc: Eric W. Biederman <ebiederm@xmission.com>
Cc: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
Cc: Ingo Molnar <mingo@kernel.org>
Cc: James Morris <james.morris@microsoft.com>
Cc: Kees Cook <keescook@chromium.org>
Cc: Oleg Nesterov <oleg@redhat.com>
Cc: Peter Zijlstra <peterz@infradead.org>
Cc: Stephen Smalley <sds@tycho.nsa.gov>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>

kernel/signal.c

@@ -65,11 +65,11 @@ static void __user *sig_handler(struct task_struct *t, int sig)
 	return t->sighand->action[sig - 1].sa.sa_handler;
 }
 
-static int sig_handler_ignored(void __user *handler, int sig)
+static inline bool sig_handler_ignored(void __user *handler, int sig)
 {
 	/* Is it explicitly or implicitly ignored? */
 	return handler == SIG_IGN ||
-		(handler == SIG_DFL && sig_kernel_ignore(sig));
+	       (handler == SIG_DFL && sig_kernel_ignore(sig));
 }
 
 static int sig_task_ignored(struct task_struct *t, int sig, bool force)