Commit 75b6930d authored by igor@rurik.mysql.com's avatar igor@rurik.mysql.com

Fixed bug #16603.

A subquery transformation changes the HAVING clause of the embedding query if the subquery contains
a GROUP BY clause. Yet the split_sum_func2 function was not applied to the modified HAVING clause.
This could result in wrong answers.
parent e1dabf65
......@@ -215,9 +215,9 @@ select * from t1 where t1.a=(select t2.a from t2 where t2.b=(select max(a) from
a
select b,(select avg(t2.a+(select min(t3.a) from t3 where t3.a >= t4.a)) from t2) from t4;
b (select avg(t2.a+(select min(t3.a) from t3 where t3.a >= t4.a)) from t2)
8 7.5
8 4.5
9 7.5
8 7.5000
8 4.5000
9 7.5000
explain extended select b,(select avg(t2.a+(select min(t3.a) from t3 where t3.a >= t4.a)) from t2) from t4;
id select_type table type possible_keys key key_len ref rows Extra
1 PRIMARY t4 ALL NULL NULL NULL NULL 3
......@@ -3131,3 +3131,29 @@ a sum
3 20
4 40
DROP TABLE t1,t2,t3;
CREATE TABLE t1 (a varchar(5), b varchar(10));
INSERT INTO t1 VALUES
('AAA', 5), ('BBB', 4), ('BBB', 1), ('CCC', 2),
('CCC', 7), ('AAA', 2), ('AAA', 4), ('BBB', 3), ('AAA', 8);
SELECT * FROM t1 WHERE (a,b) = ANY (SELECT a, max(b) FROM t1 GROUP BY a);
a b
BBB 4
CCC 7
AAA 8
EXPLAIN
SELECT * FROM t1 WHERE (a,b) = ANY (SELECT a, max(b) FROM t1 GROUP BY a);
id select_type table type possible_keys key key_len ref rows Extra
1 PRIMARY t1 ALL NULL NULL NULL NULL 9 Using where
2 DEPENDENT SUBQUERY t1 ALL NULL NULL NULL NULL 9 Using temporary; Using filesort
ALTER TABLE t1 ADD INDEX(a);
SELECT * FROM t1 WHERE (a,b) = ANY (SELECT a, max(b) FROM t1 GROUP BY a);
a b
BBB 4
CCC 7
AAA 8
EXPLAIN
SELECT * FROM t1 WHERE (a,b) = ANY (SELECT a, max(b) FROM t1 GROUP BY a);
id select_type table type possible_keys key key_len ref rows Extra
1 PRIMARY t1 ALL NULL NULL NULL NULL 9 Using where
2 DEPENDENT SUBQUERY t1 index NULL a 8 NULL 9 Using filesort
DROP TABLE t1;
......@@ -2051,3 +2051,25 @@ SELECT t1.a, SUM(b) AS sum FROM t1 GROUP BY t1.a
HAVING t2.c+sum > 20);
DROP TABLE t1,t2,t3;
#
# Test for bug #16603: GROUP BY in a row subquery with a quantifier
# when an index is defined on the grouping field
CREATE TABLE t1 (a varchar(5), b varchar(10));
INSERT INTO t1 VALUES
('AAA', 5), ('BBB', 4), ('BBB', 1), ('CCC', 2),
('CCC', 7), ('AAA', 2), ('AAA', 4), ('BBB', 3), ('AAA', 8);
SELECT * FROM t1 WHERE (a,b) = ANY (SELECT a, max(b) FROM t1 GROUP BY a);
EXPLAIN
SELECT * FROM t1 WHERE (a,b) = ANY (SELECT a, max(b) FROM t1 GROUP BY a);
ALTER TABLE t1 ADD INDEX(a);
SELECT * FROM t1 WHERE (a,b) = ANY (SELECT a, max(b) FROM t1 GROUP BY a);
EXPLAIN
SELECT * FROM t1 WHERE (a,b) = ANY (SELECT a, max(b) FROM t1 GROUP BY a);
DROP TABLE t1;
......@@ -364,22 +364,8 @@ JOIN::prepare(Item ***rref_pointer_array,
select_lex->having_fix_field= 0;
if (having_fix_rc || thd->net.report_error)
DBUG_RETURN(-1); /* purecov: inspected */
if (having->with_sum_func)
having->split_sum_func2(thd, ref_pointer_array, all_fields,
&having, TRUE);
thd->lex->allow_sum_func= save_allow_sum_func;
}
if (select_lex->inner_sum_func_list)
{
Item_sum *end=select_lex->inner_sum_func_list;
Item_sum *item_sum= end;
do
{
item_sum= item_sum->next;
item_sum->split_sum_func2(thd, ref_pointer_array,
all_fields, item_sum->ref_by, FALSE);
} while (item_sum != end);
}
if (!thd->lex->view_prepare_mode)
{
......@@ -397,6 +383,21 @@ JOIN::prepare(Item ***rref_pointer_array,
}
}
if (having && having->with_sum_func)
having->split_sum_func2(thd, ref_pointer_array, all_fields,
&having, TRUE);
if (select_lex->inner_sum_func_list)
{
Item_sum *end=select_lex->inner_sum_func_list;
Item_sum *item_sum= end;
do
{
item_sum= item_sum->next;
item_sum->split_sum_func2(thd, ref_pointer_array,
all_fields, item_sum->ref_by, FALSE);
} while (item_sum != end);
}
if (setup_ftfuncs(select_lex)) /* should be after having->fix_fields */
DBUG_RETURN(-1);
......
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