Commit 85953617 authored by Igor Babaev's avatar Igor Babaev

MDEV-17381 Wrong query result with LATERAL DERIVED optimization

          and join_cache_level=6

This bug was fixed by the patch for mdev-17382 applied to 5.5.
parent e2535dcc
......@@ -58,3 +58,44 @@ WHERE t2.id2=t.id2;
id3
1
DROP TABLE t1,t2,t3;
#
# Bug mdev-17381: equi-join of derived table with join_cache_level=4
#
CREATE TABLE t1 (
id int NOT NULL,
amount decimal DEFAULT NULL,
PRIMARY KEY (id)
) ENGINE=INNODB;
CREATE TABLE t2 (
id int NOT NULL,
name varchar(50) DEFAULT NULL,
PRIMARY KEY (id)
) ENGINE=INNODB;
INSERT INTO t1 VALUES
(1, 10.0000), (2, 20.0000), (3, 30.0000), (4, 40.0000),
(5, NULL), (6, NULL), (7, 70.0000), (8, 80.0000);
INSERT INTO t2 VALUES
(1,'A'), (2,'B'), (3,'C'), (4,'D'), (5, NULL), (6, NULL),
(7,'E'), (8,'F'), (9,'G'), (10,'H'), (11, NULL), (12, NULL);
set join_cache_level=4;
SELECT t2.id,t2.name,t.total_amt
FROM t2
LEFT JOIN
(SELECT id, sum(amount) total_amt FROM t1 GROUP BY id) AS t
ON t2.id=t.id
WHERE t2.id < 3;
id name total_amt
1 A 10
2 B 20
EXPLAIN SELECT t2.id,t2.name,t.total_amt
FROM t2
LEFT JOIN
(SELECT id, sum(amount) total_amt FROM t1 GROUP BY id) AS t
ON t2.id=t.id
WHERE t2.id < 3;
id select_type table type possible_keys key key_len ref rows Extra
1 PRIMARY t2 range PRIMARY PRIMARY 4 NULL 2 Using where
1 PRIMARY <derived2> ref key0 key0 5 test.t2.id 2
2 LATERAL DERIVED t1 eq_ref PRIMARY PRIMARY 4 test.t2.id 1
set join_cache_level=default;
DROP TABLE t1,t2;
......@@ -53,3 +53,44 @@ eval EXPLAIN $q;
eval $q;
DROP TABLE t1,t2,t3;
--echo #
--echo # Bug mdev-17381: equi-join of derived table with join_cache_level=4
--echo #
CREATE TABLE t1 (
id int NOT NULL,
amount decimal DEFAULT NULL,
PRIMARY KEY (id)
) ENGINE=INNODB;
CREATE TABLE t2 (
id int NOT NULL,
name varchar(50) DEFAULT NULL,
PRIMARY KEY (id)
) ENGINE=INNODB;
INSERT INTO t1 VALUES
(1, 10.0000), (2, 20.0000), (3, 30.0000), (4, 40.0000),
(5, NULL), (6, NULL), (7, 70.0000), (8, 80.0000);
INSERT INTO t2 VALUES
(1,'A'), (2,'B'), (3,'C'), (4,'D'), (5, NULL), (6, NULL),
(7,'E'), (8,'F'), (9,'G'), (10,'H'), (11, NULL), (12, NULL);
set join_cache_level=4;
let $q=
SELECT t2.id,t2.name,t.total_amt
FROM t2
LEFT JOIN
(SELECT id, sum(amount) total_amt FROM t1 GROUP BY id) AS t
ON t2.id=t.id
WHERE t2.id < 3;
eval $q;
eval EXPLAIN $q;
set join_cache_level=default;
DROP TABLE t1,t2;
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