Commit 8057c088 authored by Sergei Zagurskii's avatar Sergei Zagurskii Committed by Brad Fitzpatrick

reflect: optimize directlyAssignable to avoid rtype.Name call

directlyAssignable invoked rtype.Name() just to compare its result
to empty string. We really only need to check whether rtype has
name. It can be done much cheaper, by checking tflagNamed.

Benchmark: https://play.golang.org/p/V2BzESPuf2w
name                   old time/op  new time/op  delta
DirectlyAssignable-12  32.7ns ± 6%   6.6ns ± 6%  -79.80%  (p=0.008 n=5+5)

Fixes #32186

Change-Id: I1a2a167dbfddf319fba3015cb6a011bf010f99a8
Reviewed-on: https://go-review.googlesource.com/c/go/+/178518
Run-TryBot: Brad Fitzpatrick <bradfitz@golang.org>
TryBot-Result: Gobot Gobot <gobot@golang.org>
Reviewed-by: default avatarBrad Fitzpatrick <bradfitz@golang.org>
parent dca0d03b
......@@ -521,8 +521,12 @@ func (t *rtype) PkgPath() string {
return t.nameOff(ut.pkgPath).name()
}
func (t *rtype) hasName() bool {
return t.tflag&tflagNamed != 0
}
func (t *rtype) Name() string {
if t.tflag&tflagNamed == 0 {
if !t.hasName() {
return ""
}
s := t.String()
......@@ -782,7 +786,7 @@ func directlyAssignable(T, V *rtype) bool {
// Otherwise at least one of T and V must not be defined
// and they must have the same kind.
if T.Name() != "" && V.Name() != "" || T.Kind() != V.Kind() {
if T.hasName() && V.hasName() || T.Kind() != V.Kind() {
return false
}
......
......@@ -871,8 +871,12 @@ func hasPrefix(s, prefix string) bool {
return len(s) >= len(prefix) && s[:len(prefix)] == prefix
}
func (t *rtype) hasName() bool {
return t.tflag&tflagNamed != 0
}
func (t *rtype) Name() string {
if t.tflag&tflagNamed == 0 {
if !t.hasName() {
return ""
}
s := t.String()
......@@ -1563,7 +1567,7 @@ func directlyAssignable(T, V *rtype) bool {
// Otherwise at least one of T and V must not be defined
// and they must have the same kind.
if T.Name() != "" && V.Name() != "" || T.Kind() != V.Kind() {
if T.hasName() && V.hasName() || T.Kind() != V.Kind() {
return false
}
......
Markdown is supported
0%
or
You are about to add 0 people to the discussion. Proceed with caution.
Finish editing this message first!
Please register or to comment