Skip to content
Projects
Groups
Snippets
Help
Loading...
Help
Support
Keyboard shortcuts
?
Submit feedback
Contribute to GitLab
Sign in / Register
Toggle navigation
K
KTLA Study
Project overview
Project overview
Details
Activity
Releases
Repository
Repository
Files
Commits
Branches
Tags
Contributors
Graph
Compare
Issues
0
Issues
0
List
Boards
Labels
Milestones
Merge Requests
0
Merge Requests
0
CI / CD
CI / CD
Pipelines
Jobs
Schedules
Analytics
Analytics
CI / CD
Repository
Value Stream
Wiki
Wiki
Snippets
Snippets
Members
Members
Collapse sidebar
Close sidebar
Activity
Graph
Create a new issue
Jobs
Commits
Issue Boards
Open sidebar
Kirill Smelkov
KTLA Study
Commits
fff2b5e4
Commit
fff2b5e4
authored
Feb 17, 2022
by
Kirill Smelkov
Browse files
Options
Browse Files
Download
Email Patches
Plain Diff
.
parent
8b724663
Changes
1
Hide whitespace changes
Inline
Side-by-side
Showing
1 changed file
with
68 additions
and
1 deletion
+68
-1
KBackery.tla
KBackery.tla
+68
-1
No files found.
KBackery.tla
View file @
fff2b5e4
...
...
@@ -2,12 +2,79 @@
CONSTANT N \* number of processes
\* How the algorithm is designed:
\* 1. start from algorithm directly created from words:
\*
\* process(i \in 1..N)
\* variable j \in Nat
\* {
\* while (TRUE) {
\* \* > get a ticket
\* ticket[i] := 1 + max(ticket[j] \A j \in 1..N)
\*
\* \* > wait till when got ticket is < all other tickets
\* for j \in 1..N {
\* Lwait_jbehind:
\* while (~(ticket[j]=0 \/ ticket[i] < ticket[j]))
\* goto Lwait_jbehind;
\* }
\*
\* \* > service
\* cs: skip
\*
\* \* > end - recycle the ticket
\* ticket[i] := 0
\* }
\* }
\* 2. Notice that there might be deadlock if proc[i] and proc[k] race on
\* entry/entry: in that case ticket[i] might be = ticket[k] and both processes will
\* deadlock looping on Lwait_jbehind.
\*
\* P1 P2
\* t1=0 t2=0
\* t1=1 t2=1
\* while(t1>=t2) while(t2>=t1)
\*
\* FIX: `ticket[i] < ticket[j]` => `(ticket[i],i) < (ticket[j],j)`
\* 3. Check wait[i]/entry[k] for race.
\* If entry[i]/entry[k] raced and entry[k] lasts longer and overlaps with
\* wait[i], it is possible for both proc[i] and proc[k] to enter cs at the same time:
\*
\* P1 P2
\* t1=0 t2=0
\* # entry # entry
\* <read t2 <read t1
\* >read t2(0) >read t1(0)
\* t2=1
\*
\* # wait
\* read t1(0)
\* t1=1
\* # wait <CS
\* read t2(1) ...
\* Y: (t1,1)<(t2,2) ...
\* | ...
\* v ...
\* <CS ... <-- ~ME(cs)
\*
\*
\* FIX: Introduce inentry[i] and before Lwait_jbehind wait for proc[j] to first
\* complete its entry phase if it was in there.
\* 4. Check wait[i]/wait[j] for race.
\* No variables are assigned in wait => there cannot be any race here.
(*******
--algorithm KBackery
variables
\* > *[i] is located on memory unit of proc[i]
ticket = [i \in 1..N |-> 0] \* ticket=0 means "inactive"
XXX or `^\infty^' ?
ticket = [i \in 1..N |-> 0] \* ticket=0 means "inactive"
inentry = [i \in 1..N |-> FALSE] \* T while in entry. To avoid ~ME(cs) on wait/entry race
process(i \in 1..N)
...
...
Write
Preview
Markdown
is supported
0%
Try again
or
attach a new file
Attach a file
Cancel
You are about to add
0
people
to the discussion. Proceed with caution.
Finish editing this message first!
Cancel
Please
register
or
sign in
to comment