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Douglas Anderson authored
As documented in dwc2_calculate_dynamic_fifo(), host_rx_fifo_size should really be: 2 * ((Largest Packet size / 4) + 1 + 1) + n with n = number of host channel. We have 9 host channels, so 2 * ((1024/4) + 2) + 9 = 516 + 9 = 525 We've got 960 / 972 total_fifo_size on rk3288 (and presumably on rk3066) and 525 + 128 + 256 = 909 so we're still under on both ports even when we increment by 5. In the future, it would be nice if dwc2_calculate_dynamic_fifo() could handle the "too small" FIFO case and come up with something more dynamically. When we do that we can figure out how to allocate the extra 48 / 60 bytes of FIFO that we're currently wasting. NOTE: no known bugs are fixed by this patch, but it seems like a simple fix and ought to fix someone. Acked-by: John Youn <johnyoun@synopsys.com> Signed-off-by: Douglas Anderson <dianders@chromium.org> Reviewed-by: Kever Yang <kever.yang@rock-chips.com> Tested-by: Heiko Stuebner <heiko@sntech.de> Signed-off-by: Felipe Balbi <balbi@kernel.org>
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