gpu: host1x: Call ->remove() only when a device is bound

When a driver's ->probe() function fails, the host1x bus must not call
its ->remove() function because the driver will already have cleaned up
in the error handling path in ->probe().
Signed-off-by: Thierry Reding <treding@nvidia.com>

drivers/gpu/host1x/bus.c

@@ -116,7 +116,10 @@ static void host1x_subdev_register(struct host1x_device *device,
 	if (list_empty(&device->subdevs)) {
 		err = device->driver->probe(device);
 		if (err < 0)
-			dev_err(&device->dev, "probe failed: %d\n", err);
+			dev_err(&device->dev, "probe failed for %ps: %d\n",
+				device->driver, err);
+		else
+			device->bound = true;
 	}
 }
 
@@ -130,10 +133,12 @@ static void __host1x_subdev_unregister(struct host1x_device *device,
 	 * If all subdevices have been activated, we're about to remove the
 	 * first active subdevice, so unload the driver first.
 	 */
-	if (list_empty(&device->subdevs)) {
+	if (list_empty(&device->subdevs) && device->bound) {
 		err = device->driver->remove(device);
 		if (err < 0)
 			dev_err(&device->dev, "remove failed: %d\n", err);
+
+		device->bound = false;
 	}
 
 	/*

include/linux/host1x.h

@@ -272,6 +272,8 @@ struct host1x_device {
 
 	struct mutex clients_lock;
 	struct list_head clients;
+
+	bool bound;
 };
 
 static inline struct host1x_device *to_host1x_device(struct device *dev)