idpf: Interpret .set_channels() input differently
Unlike ice, idpf does not check, if user has requested at least 1 combined channel. Instead, it relies on a check in the core code. Unfortunately, the check does not trigger for us because of the hacky .set_channels() interpretation logic that is not consistent with the core code. This naturally leads to user being able to trigger a crash with an invalid input. This is how: 1. ethtool -l <IFNAME> -> combined: 40 2. ethtool -L <IFNAME> rx 0 tx 0 combined number is not specified, so command becomes {rx_count = 0, tx_count = 0, combined_count = 40}. 3. ethnl_set_channels checks, if there is at least 1 RX and 1 TX channel, comparing (combined_count + rx_count) and (combined_count + tx_count) to zero. Obviously, (40 + 0) is greater than zero, so the core code deems the input OK. 4. idpf interprets `rx 0 tx 0` as 0 channels and tries to proceed with such configuration. The issue has to be solved fundamentally, as current logic is also known to cause AF_XDP problems in ice [0]. Interpret the command in a way that is more consistent with ethtool manual [1] (--show-channels and --set-channels) and new ice logic. Considering that in the idpf driver only the difference between RX and TX queues forms dedicated channels, change the correct way to set number of channels to: ethtool -L <IFNAME> combined 10 /* For symmetric queues */ ethtool -L <IFNAME> combined 8 tx 2 rx 0 /* For asymmetric queues */ [0] https://lore.kernel.org/netdev/20240418095857.2827-1-larysa.zaremba@intel.com/ [1] https://man7.org/linux/man-pages/man8/ethtool.8.html Fixes: 02cbfba1 ("idpf: add ethtool callbacks") Reviewed-by: Przemek Kitszel <przemyslaw.kitszel@intel.com> Reviewed-by: Igor Bagnucki <igor.bagnucki@intel.com> Signed-off-by: Larysa Zaremba <larysa.zaremba@intel.com> Tested-by: Krishneil Singh <krishneil.k.singh@intel.com> Reviewed-by: Simon Horman <horms@kernel.org> Signed-off-by: Jacob Keller <jacob.e.keller@intel.com> Signed-off-by: Paolo Abeni <pabeni@redhat.com>
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