sched/fair: Simplify the update_sd_pick_busiest() logic
When comparing the current struct sched_group with the yet-busiest domain in update_sd_pick_busiest(), if the two groups have the same group type, we're currently doing a bit of unnecessary work for any group >= group_misfit_task. We're comparing the two groups, and then returning only if false (the group in question is not the busiest). Otherwise, we break out, do an extra unnecessary conditional check that's vacuously false for any group type > group_fully_busy, and then always return true. Let's just return directly in the switch statement instead. This doesn't change the size of vmlinux with llvm 17 (not surprising given that all of this is inlined in load_balance()), but it does shrink load_balance() by 88 bytes on x86. Given that it also improves readability, this seems worth doing. Signed-off-by: David Vernet <void@manifault.com> Signed-off-by: Ingo Molnar <mingo@kernel.org> Reviewed-by: Vincent Guittot <vincent.guittot@linaro.org> Reviewed-by: Valentin Schneider <vschneid@redhat.com> Link: https://lore.kernel.org/r/20240206043921.850302-4-void@manifault.com
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