sched: Fix the group_imb logic
On a 2*6*2 machine something like: taskset -c 3-11 bash -c 'for ((i=0;i<9;i++)) do while :; do :; done & done' _should_ result in 9 busy CPUs, each running 1 task. However it didn't quite work reliably, most of the time one cpu of the second socket (6-11) would be idle and one cpu of the first socket (0-5) would have two tasks on it. The group_imb logic is supposed to deal with this and detect when a particular group is imbalanced (like in our case, 0-2 are idle but 3-5 will have 4 tasks on it). The detection phase needed a bit of a tweak as it was too weak and required more than 2 avg weight tasks difference between idle and busy cpus in the group which won't trigger for our test-case. So cure that to be one or more avg task weight difference between cpus. Once the detection phase worked, it was then defeated by the f_b_g() tests trying to avoid ping-pongs. In particular, this_load >= max_load triggered because the pulling cpu (the (first) idle cpu in on the second socket, say 6) would find this_load to be 5 and max_load to be 4 (there'd be 5 tasks running on our socket and only 4 on the other socket). Signed-off-by: Peter Zijlstra <a.p.zijlstra@chello.nl> Cc: Nikhil Rao <ncrao@google.com> Cc: Venkatesh Pallipadi <venki@google.com> Cc: Suresh Siddha <suresh.b.siddha@intel.com> Cc: Mike Galbraith <efault@gmx.de> LKML-Reference: <new-submission> Signed-off-by: Ingo Molnar <mingo@elte.hu>
Showing
Please register or sign in to comment