btrfs: tree-checker: Fix wrong check on max devid
[BUG] The following script will cause false alert on devid check. #!/bin/bash dev1=/dev/test/test dev2=/dev/test/scratch1 mnt=/mnt/btrfs umount $dev1 &> /dev/null umount $dev2 &> /dev/null umount $mnt &> /dev/null mkfs.btrfs -f $dev1 mount $dev1 $mnt _fail() { echo "!!! FAILED !!!" exit 1 } for ((i = 0; i < 4096; i++)); do btrfs dev add -f $dev2 $mnt || _fail btrfs dev del $dev1 $mnt || _fail dev_tmp=$dev1 dev1=$dev2 dev2=$dev_tmp done [CAUSE] Tree-checker uses BTRFS_MAX_DEVS() and BTRFS_MAX_DEVS_SYS_CHUNK() as upper limit for devid. But we can have devid holes just like above script. So the check for devid is incorrect and could cause false alert. [FIX] Just remove the whole devid check. We don't have any hard requirement for devid assignment. Furthermore, even devid could get corrupted by a bitflip, we still have dev extents verification at mount time, so corrupted data won't sneak in. This fixes fstests btrfs/194. Reported-by: Anand Jain <anand.jain@oracle.com> Fixes: ab4ba2e1 ("btrfs: tree-checker: Verify dev item") CC: stable@vger.kernel.org # 5.2+ Signed-off-by: Qu Wenruo <wqu@suse.com> Reviewed-by: David Sterba <dsterba@suse.com> Signed-off-by: David Sterba <dsterba@suse.com>
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