Commit b68b97a7 authored by Guido van Rossum's avatar Guido van Rossum

Subtle change to run() loop: when a deadlock is detected, set

_deadline to None, to prevent reporting the same timeout more than
once.  Added a helpful comment too. :-)
parent 1535c41c
......@@ -824,9 +824,12 @@ class TimeoutThread(threading.Thread):
while 1:
self._cond.acquire()
try:
while self._client is None:
while self._deadline is None:
self._cond.wait()
howlong = self._deadline - time.time()
if howlong <= 0:
# Prevent reporting timeout more than once
self._deadline = None
client = self._client # For the howlong <= 0 branch below
finally:
self._cond.release()
......
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