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Sean McGivern authored
If we don't call #to_a, we're relying on the members already being loaded from elsewhere. Otherwise we'll do a separate query for each user: [1] pry(main)> Project.first.team.members.include?(User.first) Project Load (0.7ms) SELECT "projects".* FROM "projects" ORDER BY "projects"."id" ASC LIMIT 1 ↳ (pry):3 User Load (1.8ms) SELECT "users".* FROM "users" ORDER BY "users"."id" ASC LIMIT 1 ↳ (pry):3 User Exists (0.6ms) SELECT 1 AS one FROM "users" INNER JOIN "project_authorizations" ON "users"."id" = "project_authorizations"."user_id" WHERE "project_authorizations"."project_id" = $1 AND "users"."id" = $2 LIMIT 1 [["project_id", 1], ["id", 1]] ↳ (pry):3 => true [2] pry(main)> Project.first.team.members.to_a.include?(User.first) Project Load (12.8ms) SELECT "projects".* FROM "projects" ORDER BY "projects"."id" ASC LIMIT 1 ↳ (pry):1 User Load (9.6ms) SELECT "users".* FROM "users" INNER JOIN "project_authorizations" ON "users"."id" = "project_authorizations"."user_id" WHERE "project_authorizations"."project_id" = $1 [["project_id", 1]] ↳ (pry):1 User Load (0.6ms) SELECT "users".* FROM "users" ORDER BY "users"."id" ASC LIMIT 1 ↳ (pry):1 => true
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