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Benjamin Herrenschmidt authored
If the interrupt and the timeout happen roughly at the same time, we can get into a situation where the timer function is run while the interrupt has already been processed. In this case, the timer function might end up doing an add_timer on an already pending timer, causing a BUG_ON() to trigger. Instead, just skip the whole timeout operation if we see that the timer is pending. The spinlock ensures that the only way that happens is if we already started a new operation and thus the timeout can be ignored. Signed-off-by: Benjamin Herrenschmidt <benh@kernel.crashing.org>
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