[PATCH] parport: fix documentation

Fix documentation to actually match the code.
Signed-off-by: Arnaud Giersch <arnaud.giersch@free.fr>
Signed-off-by: Andrew Morton <akpm@osdl.org>
Signed-off-by: Linus Torvalds <torvalds@osdl.org>

Documentation/parport-lowlevel.txt

@@ -1068,7 +1068,7 @@ SYNOPSIS
 
 struct parport_operations {
 	...
-	void (*write_status) (struct parport *port, unsigned char s);
+	void (*write_control) (struct parport *port, unsigned char s);
 	...
 };
 
@@ -1097,9 +1097,9 @@ SYNOPSIS
 
 struct parport_operations {
 	...
-	void (*frob_control) (struct parport *port,
-	                      unsigned char mask,
-			      unsigned char val);
+	unsigned char (*frob_control) (struct parport *port,
+				       unsigned char mask,
+				       unsigned char val);
 	...
 };
 

drivers/parport/ieee1284.c

@@ -61,10 +61,10 @@ static void timeout_waiting_on_port (unsigned long cookie)
  *	set to zero, it returns immediately.
  *
  *	If an interrupt occurs before the timeout period elapses, this
- *	function returns one immediately.  If it times out, it returns
- *	a value greater than zero.  An error code less than zero
- *	indicates an error (most likely a pending signal), and the
- *	calling code should finish what it's doing as soon as it can.
+ *	function returns zero immediately.  If it times out, it returns
+ *	one.  An error code less than zero indicates an error (most
+ *	likely a pending signal), and the calling code should finish
+ *	what it's doing as soon as it can.
  */
 
 int parport_wait_event (struct parport *port, signed long timeout)
@@ -110,7 +110,7 @@ int parport_wait_event (struct parport *port, signed long timeout)
  *
  *	If the status lines take on the desired values before the
  *	timeout period elapses, parport_poll_peripheral() returns zero
- *	immediately.  A zero return value greater than zero indicates
+ *	immediately.  A return value greater than zero indicates
  *	a timeout.  An error code (less than zero) indicates an error,
  *	most likely a signal that arrived, and the caller should
  *	finish what it is doing as soon as possible.