genirq: Validate action before dereferencing it in handle_irq_event_percpu()
commit 71f64340 changed the handling of irq_desc->action from CPU 0 CPU 1 free_irq() lock(desc) lock(desc) handle_edge_irq() if (desc->action) { handle_irq_event() action = desc->action unlock(desc) desc->action = NULL handle_irq_event_percpu(desc, action) action->xxx to CPU 0 CPU 1 free_irq() lock(desc) lock(desc) handle_edge_irq() if (desc->action) { handle_irq_event() unlock(desc) desc->action = NULL handle_irq_event_percpu(desc, action) action = desc->action action->xxx So if free_irq manages to set the action to NULL between the unlock and before the readout, we happily dereference a null pointer. We could simply revert 71f64340, but we want to preserve the better code generation. A simple solution is to change the action loop from a do {} while to a while {} loop. This is safe because we either see a valid desc->action or NULL. If the action is about to be removed it is still valid as free_irq() is blocked on synchronize_irq(). CPU 0 CPU 1 free_irq() lock(desc) lock(desc) handle_edge_irq() handle_irq_event(desc) set(INPROGRESS) unlock(desc) handle_irq_event_percpu(desc) action = desc->action desc->action = NULL while (action) { action->xxx ... action = action->next; sychronize_irq() while(INPROGRESS); lock(desc) clr(INPROGRESS) free(action) That's basically the same mechanism as we have for shared interrupts. action->next can become NULL while handle_irq_event_percpu() runs. Either it sees the action or NULL. It does not matter, because action itself cannot go away before the interrupt in progress flag has been cleared. Fixes: commit 71f64340 "genirq: Remove the second parameter from handle_irq_event_percpu()" Reported-by: zyjzyj2000@gmail.com Signed-off-by: Thomas Gleixner <tglx@linutronix.de> Cc: Huang Shijie <shijie.huang@arm.com> Cc: Jiang Liu <jiang.liu@linux.intel.com> Cc: Peter Zijlstra <peterz@infradead.org> Cc: stable@vger.kernel.org Link: http://lkml.kernel.org/r/alpine.DEB.2.11.1601131224190.3575@nanos
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